Unstretched Spring and Angular Velocity Problem

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Homework Help Overview

The problem involves a disk being held by a spring on a frictionless table, with the disk orbiting in a circle at a specified angular velocity. The objective is to determine how much the spring is stretched, given the mass of the disk, the unstretched length of the spring, and its stiffness constant.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between circular motion and spring extension, referencing both Hooke's law and the dynamics of circular motion. There are attempts to derive a formula for the spring extension based on the given parameters. Some participants express confusion about unit conversions and the implications of not having the linear velocity.

Discussion Status

There is an ongoing exploration of unit conversions and their impact on the calculations. Some participants have provided guidance on ensuring standard units are used, while others are questioning the derivation and its correctness. The discussion reflects a collaborative effort to clarify the problem setup and assumptions.

Contextual Notes

Participants note the importance of using standard units for calculations, specifically converting lengths and stiffness constants from centimeters to meters. There is also mention of the challenge posed by not having the linear velocity directly available for calculations.

BitterSuites
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[SOLVED] Unstretched Spring and Angular Velocity Problem

Homework Statement



A disk of mass 73 kg is held by a spring of unstretched length 88 cm and stiffness constant 430 N/cm, and rests on a frictionless table. It is then orbited in a circle at angular velocity .675 rad/s.

By how much is the spring stretched? Answer in units of cm.

Homework Equations



After a bit of derivation, I came up with x = r/((k/mw^2)-1).

The Attempt at a Solution



r = 88
k = 430
m= 73
w = .675

It does not seem to work out. Am I being to complicated about it? Any help/hand-holding is greatly appreciated.
 
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Force acting on the disc in circular motion== mv^2/r

Now use hook's law to calculate extension..
 
BitterSuites said:
After a bit of derivation, I came up with x = r/((k/mw^2)-1).
Looks good to me.

The Attempt at a Solution



r = 88
k = 430
m= 73
w = .675
Make sure you are using standard units. Express lengths (and k) in terms of meters, not cm.
 
Thanks for the catch on conversion. I changed length to .88 and K to 4.3, getting an answer in m. I then converted it to cm but the online system still says I am incorrect.

I can't use mv^2/r because I don't have v. That is why I did that insane derivation.

Or am I wrong?

I think I'm a few baby steps away from having this.
 
BitterSuites said:
I changed length to .88 and K to 4.3...
Redo that last one. :wink:
 
Uh oh. Did I go the wrong way with it? 43000N/m?
 
That's better.
 
Oh, thank you so much *sighs in relief*

Converting correctly makes the problem work. Who knew? :D
 

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