Upper Bound of H in GCSE Maths

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The discussion focuses on calculating the upper bound of H in a GCSE Maths problem. The user calculated H using the upper bounds of v and g but arrived at a different answer than the model solution. It was clarified that the upper bound of 1/g should be determined using the lower bound of g. Additionally, the correct approach for subtraction was explained, emphasizing that the upper and lower bounds must reflect the calculations accurately. Understanding these principles is crucial for correctly determining upper and lower bounds in mathematical problems.
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Hi all

I have another upper/low bound question, i have attached the question to this thread.

The bit i am having trouble with is part (II) i.e. calculate the upper bound of H.

I attempted this and got: -

(24.45^2)/(2*9.85) = 30.34530457

H = 30.3 (3 sig fig)

The problem is that my answer differs from the model answer shown in the attachment, the reason why i did what i did was because the question stated find the Upper Bound of H, so i thought i need to use the upper bound of v & g to calculate the upper bound of H, why am i incorrect?

Thanks
 

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The upper bound of 1/g is found when the lower bound of g is used.

Same thing with subtraction: upper bound of 1.7 - 1.2 is 1.75 - 1.15 = 0.6.
And lower bound is 0.4. With your method upper and lower bound would be the same as the calculated difference itself...
 

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