1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Urgent projectile motion

  1. Sep 1, 2012 #1
    Urgent!!!! projectile motion

    Heyy every1
    Q Exactly 2.7s after a projectile is fired into the air from the ground ,it is observed to have a velocity v = (8.8i+4.5 j) m/s where the x-axis is horizontal and the y axis is positive upward .
    a)Determine the horizontal range of the projectile
    b)Determine the maximum height above the ground
    c)Determine the speed of motion just above the projectile strikes the ground .
    d)Determine the angle of the motion just before the projectile strikes the ground .

    I managed to do the first two parts where max height is 49m and range is 56 m .Bt i do not noe how to go abt the c) and d) part
  2. jcsd
  3. Sep 1, 2012 #2
    Re: Urgent!!!! projectile motion

    What is horizontal component of the velocity? What is the vertical component of final velocity?
  4. Sep 1, 2012 #3
    Re: Urgent!!!! projectile motion

    well i was able to calaculate the max height and range using horizontal velocity to be 8.8 and vertical final velocity as 4.5 at 2.7 s .This much information only was given n the question tht s why i m confused
  5. Sep 1, 2012 #4


    User Avatar
    Gold Member

    Re: Urgent!!!! projectile motion

    For d), knowing the horizontal and vertical components of initial velocity should help you. You know that the trajectory is parabolic and so just prior to impact, use the condition,[tex] -v_{fy} \hat{y} = v_{oy} \hat{y}. [/tex]
  6. Sep 1, 2012 #5
    Re: Urgent!!!! projectile motion

    Horizontal velocity(i component) remains constant since no forces acting on it.
    Vertically(j component) there is negative acceleration.
    Sketch a graph of velocity vs. time. Upward as positive.
    Δv/Δt is constant. You can find initial vertical velocity from acceleration equation.

    Speed it the vector sum of vertical and horizontal velocity.

    Angle of projection is just the tangent of vertical and horizontal velocity.
    Last edited: Sep 1, 2012
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook