- #1

mmmboh

- 407

- 0

Alright so I found div F=3x

^{2}+3y

^{2}+3z

^{2}

The integral then becomes the triple integral of the divergence of F times the derivative of the volume.

Changing into spherical coordinates, the integral becomes [tex]3\int_{0}^{2\pi}\int_{0}^{\pi}\int_{0}^{1}p^{4}sin{\phi}dpd{\phi}d{\theta} [/tex] which ends up equaling [tex]2.4{\pi}[/tex].

Is this correct?

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