Find Io, find V, find Vo
V = IR
And if these are right:
(voltage across series resistor) = [ (resistance)/(total series resistance) ](total input V)
Current division (only for two resistors in parallel):
(current through parallel resistor) = [ (OTHER resistance)/(total parallel resistance) ](total incoming current)
The Attempt at a Solution
I feel like I can't go anywhere else in the problem without first finding the current Io. I'm not sure how to use voltage division law properly. Does it only apply to one wire (one node)?
Same goes for current division law but I think I understand it better:
I simplified all resistors except for the 24Ω resistor. So I am left with 8Ω and 24Ω resistors in parallel, along with the 8 amp total current coming in.
Trying to solve Io with the current division law above, I get:
Io = (8Ω / 6Ω)8A = 10.6A
but it is wrong, supposedly. ( 6Ω in the equation because (1/8 + 1/24)^-1 = 6 , unless I got something wrong. )
Last edited by a moderator: