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Color_of_Cyan
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Homework Statement
http://imageshack.us/a/img26/4592/homeworkprintprob.jpg Find the voltage V0 in the network.
Homework Equations
V = IR
Voltage Division:
(Voltage across series resistor) = [(resistance) / total series resistance)](total input V)
Current Division (for 2 parallel resistors):
(current across parallel resistor) = [(other resistor) / (sum of parallel resistors)](total incoming current)]
The Attempt at a Solution
I can simplify the 1k and 3k resistors to 4k no matter what.
I'm not sure if I can simplify the 6k and 12k on the bottom as parallel though, but they will be 4k.
4k + 4k + 2k in series becomes 10k, assuming you can do that with the current source.
Then 10k + 6k makes
R total = 16k ohm, and then I tot = 24 mA
V = IR means Vtot = 384V.
Then voltage division would make
V0 = [ (6k)/(6k+10k) ](384V) = 144V
would this be correct?
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