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Color_of_Cyan

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## Homework Statement

http://imageshack.us/a/img26/4592/homeworkprintprob.jpg Find the voltage V

_{0}in the network.

## Homework Equations

V = IR

Voltage Division:

(Voltage across series resistor) = [(resistance) / total series resistance)](total input V)

Current Division (for 2 parallel resistors):

(current across parallel resistor) = [(other resistor) / (sum of parallel resistors)](total incoming current)]

## The Attempt at a Solution

I can simplify the 1k and 3k resistors to 4k no matter what.

I'm not sure if I can simplify the 6k and 12k on the bottom as parallel though, but they will be 4k.

4k + 4k + 2k in series becomes 10k, assuming you can do that with the current source.

Then 10k + 6k makes

R total = 16k ohm, and then I tot = 24 mA

V = IR means Vtot = 384V.

Then voltage division would make

V

_{0}= [ (6k)/(6k+10k) ](384V) = 144V

would this be correct?

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