1. The problem statement, all variables and given/known data http://imageshack.us/a/img26/4592/homeworkprintprob.jpg [Broken] Find the voltage V0 in the network. 2. Relevant equations V = IR Voltage Division: (Voltage across series resistor) = [(resistance) / total series resistance)](total input V) Current Division (for 2 parallel resistors): (current across parallel resistor) = [(other resistor) / (sum of parallel resistors)](total incoming current)] 3. The attempt at a solution I can simplify the 1k and 3k resistors to 4k no matter what. I'm not sure if I can simplify the 6k and 12k on the bottom as parallel though, but they will be 4k. 4k + 4k + 2k in series becomes 10k, assuming you can do that with the current source. Then 10k + 6k makes R total = 16k ohm, and then I tot = 24 mA V = IR means Vtot = 384V. Then voltage division would make V0 = [ (6k)/(6k+10k) ](384V) = 144V would this be correct?