Uses of mean, standard deviation and Z tables

AI Thread Summary
To determine the guaranteed lifetime for the LEDs, the manufacturer needs to find the value of X such that the probability of failure (P(F)) is 0.02. This involves using the mean lifetime of 2048 hours and a standard deviation of 40 hours to convert to the standard normal distribution using Z-scores. The Z-score corresponding to the 2% failure rate is approximately -2.05. By applying the formula X = μ + Zσ, the manufacturer can calculate the guaranteed lifetime. This process ensures that only 2% of the bulbs will be returned for not meeting the specified lifetime.
sazzlefrazzle
Hey i was wondering if anyone could help me with this question at all? I don't have a clue about the calculations and would be grateful if it could be explained to me! I'm really struggling! Thanks

Some light emitting diodes are tested and a sample is found to have a mean lifetime of 2048 hours and a standard deviation of 40 hours. The manufacturer wants to give a guaranteed lifetime for the LED’s on the box so that only 2% of the bulbs will be returned for not lasting for the guaranteed lifetime. Using Z table standard normal distribution show your calculation giving the lifetime he should put on the box.
 
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The question is asking you to find the lifetime X such that the probability of failure P(F) is less then or equal to .02.
 
Do you know how to change from a normal distribution with mean \mu and standard deviation \sigma to the standard normal distribution? If not, why in the world are you doing a problem like this?
 
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