Using Constant-Volume Specific Heat for Calculating Change of Internal Energy?

Click For Summary
Using constant-volume specific heat (C_v) to calculate the change of internal energy (ΔU) is valid for ideal gases across all processes, including isobaric processes. The relationship ΔU = nC_v(T2 - T1) holds true because internal energy is a state variable, and the unique properties of ideal gases allow this simplification. The confusion arises when considering the definition of heat capacity, which varies depending on the process conditions. In constant-pressure processes, while the heat capacity C_p is used for heat transfer calculations, the change in internal energy still relies on C_v due to the nature of ideal gas behavior. Thus, C_v remains the appropriate choice for calculating ΔU regardless of the process type.
KFC
Messages
477
Reaction score
4
I note that in many case, we always use the constant-volume specific heat to calculate the change of internal energy.

For example, in a adiabatic process (P1, V1, T1) to (P2, V2, T2), since internal energy is state variable, we always like to build a fictitious isochoric process from (P1, V1, T1) to (P1', V1, T2) and isobaric process from (P1', V1, T2) to (P2, V2, T2) so that the total change of internal energy be

\Delta U = n C_v(T2-T1) + nC_p(T2-T2) = n C_v(T2-T1)

Is this always true? There is a chapter about isobaric process in my text. The author use the constant-volume specific heat to calculate the change of internal energy

\Delta U = nC_v \Delta T

the work done by the ideal gas is

\Delta W = nR\Delta T

according to first law

\Delta Q = \Delta U + \Delta W = nC_v\Delta T + nR\Delta T = nC_p \Delta T

this results is really confusing me. I wonder why don't we just use the constant-pressure specific heat to calculate the change of internal energy for isobaric process? But if we use C_p to calculate \Delta U, the result will be different ... well all of these doubts is concluded in the following questions:

1) will it ALWAYS be true to use constant-volume specific heat to calculate the change of internal energy? No matter what process is concerned (even for isobaric process)?

2) The definition of heat capacity is: the change of heat per mole per degree. So why we keep use specific heat to calculate the change of internal energy instead of the change heat?


Thanks.
 
  • Like
Likes 1 person
Physics news on Phys.org
KFC said:
1) will it ALWAYS be true to use constant-volume specific heat to calculate the change of internal energy? No matter what process is concerned (even for isobaric process)?

Only for an ideal gas, https://www.physicsforums.com/showpost.php?p=2009417&postcount=2". This is a result of the unique non-interaction of atoms in an ideal gas.

It might help to look at it this way: It's always true, for any system, that

dU=T\,dS-d(PV)+V\,dP

For a constant-pressure process (dP=0), the heat capacity

C_P=T\left(\frac{\partial S}{\partial T}\right)_P=C_V+nR

for an ideal gas, and d(PV)=nR\,dT for an ideal gas. So

\left(\frac{\partial U}{\partial T}\right)_P=C_V

As you can see, dU=C_V dT holds for constant-volume and constant-pressure processes. In fact it holds for all processes (for an ideal gas).

KFC said:
2) The definition of heat capacity is: the change of heat per mole per degree. So why we keep use specific heat to calculate the change of internal energy instead of the change heat?

The definition of heat capacity is T\left(\frac{\partial S}{\partial T}\right)_X, the heat needed to increase the temperature of a system by one degree under some condition X (there are also the molar heat capacity and specific heat capacity, which are normalized by amount of matter and mass, respectively).
 
Last edited by a moderator:
  • Like
Likes 1 person
Mapes said:
Only for an ideal gas, https://www.physicsforums.com/showpost.php?p=2009417&postcount=2". This is a result of the unique non-interaction of atoms in an ideal gas.

It might help to look at it this way: It's always true, for any system, that

dU=T\,dS-d(PV)+V\,dP

For a constant-pressure process (dP=0), the heat capacity

C_P=T\left(\frac{\partial S}{\partial T}\right)_P=C_V+nR

for an ideal gas, and d(PV)=nR\,dT for an ideal gas. So

\left(\frac{\partial U}{\partial T}\right)_P=C_V

As you can see, dU=C_V dT holds for constant-volume and constant-pressure processes. In fact it holds for all processes (for an ideal gas).



The definition of heat capacity is T\left(\frac{\partial S}{\partial T}\right)_X, the heat needed to increase the temperature of a system by one degree under some condition X (there are also the molar heat capacity and specific heat capacity, which are normalized by amount of matter and mass, respectively).

Thanks again. It is really helpful.
 
Last edited by a moderator:
Thread 'What is the pressure of trapped air inside this tube?'
As you can see from the picture, i have an uneven U-shaped tube, sealed at the short end. I fill the tube with water and i seal it. So the short side is filled with water and the long side ends up containg water and trapped air. Now the tube is sealed on both sides and i turn it in such a way that the traped air moves at the short side. Are my claims about pressure in senarios A & B correct? What is the pressure for all points in senario C? (My question is basically coming from watching...

Similar threads

Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
10K
Replies
5
Views
544
  • · Replies 61 ·
3
Replies
61
Views
7K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
10
Views
2K