Using dimensions to derive an equation

  • Thread starter Thread starter Darren Byrne
  • Start date Start date
  • Tags Tags
    Derive Dimensions
AI Thread Summary
The discussion focuses on deriving an equation for the frequency of a simple pendulum using dimensional analysis. The user starts with the relationship f = 1/T and identifies the dimensions of frequency as [f] = T^-1. They also determine the dimensions for gravitational field strength as [g] = LT^-2 but struggle to connect these concepts. A suggestion is made to express the output form in terms of input forms raised to unknown powers, guiding the user on how to set up the equation for further analysis. The conversation emphasizes the importance of dimensional consistency in deriving relationships in physics.
Darren Byrne
Messages
2
Reaction score
0

Homework Statement



The frequency of a simple pendulum depends only on its length and the gravitational field strength. Use dimensions to derive a possible form for the equation for this frequency.

Homework Equations


[/B]
Not sure. I was looking at f = 1/T as a starting point and g = F/m

The Attempt at a Solution


[/B]
I'm fairy new to physics. This question is in the opening chapter on 'dimensions'. I fairly easily worked my way through the first three questions but this one (the last one) is a little trickier for me. I made an attempt (below) but I'm guessing its wrong.

I started with f = 1 /T since it's the only equation I know currently for frequency.

From there I wrote down the dimensions for frequency as [f] = 1 x T-1

Now I'm stuck. Since this is the opening chapter I doubt they expect me to know the relationship between gravitational field strength, length and frequency so how do I proceed from here?

I thought perhaps I should find the dimensions for gravitational field strength so used g = F/m

and from there got [g] = LT-2

I made a stab in the dark then and expressed frequency as f = l / T3

I would appreciate any tips on how a beginner would approach a question like this.

Cheers
 
Physics news on Phys.org
Dimensional analysis works like this. First, express each of the inputs and the output in the form MxLyTz, etc. (so, if electric charge were to feature then there could also be a Qt term, etc.). A force would be MLT-2.
Next, write an equation in which the output form equals a product of input forms raised to unknown powers. E.g. If you wanted a relationship between a force a mass and an acceleration then you would write (MLT-2)=(M)q(LT-2)r and solve for q, r.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top