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Using double in tegrals to find the area/volume

  1. Oct 27, 2009 #1
    1. The problem statement, all variables and given/known data
    1. r=4+3*cos([tex]\theta[/tex])
    2.bounded by the cylinders x^2+y^2=r^2 and y^2+z^2=r^2
    3. the solid enclosed by the parabolic cylinder y=x^2 and the planes z=3y and z=2+y


    2. Relevant equations



    3. The attempt at a solution
    1. i set up the double integral of r and with r= o to 4+3*cos([tex]\theta[/tex]), [tex]\theta[/tex]=0 to 2 pi
    2. i set up the double integral of (r^2-y^2)^(1/2) and with x=-(r^2-y^2)^(1/2) to x= (r^2-y^2)^(1/2), y= -r to y=r. and muliply the volume by two due to the symmetricity of the graph
    3. i know i should find the volume of one and subtract the volume of the second one. but thats all i know. i dont know how to set up the integrals

    can anyone tell me what i did in 1 and 2 is right or not and help me w/ 3? thx
     
  2. jcsd
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