Using Gauss's Law to Calculate Electric Field of a Charged Thread

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Discussion Overview

The discussion revolves around the application of Gauss's Law to calculate the electric field generated by a uniformly charged finite thread. Participants explore the conditions under which Gauss's Law can be applied, the implications of symmetry in charge distributions, and the potential need for numerical solutions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question whether Gauss's Law can be applied to a uniformly charged finite thread, citing the lack of constant direction of the electric field as a concern.
  • Others argue that Gauss's Law can be used for any charge distribution, but note that it may not yield an analytical solution for non-symmetric cases.
  • A participant mentions that the potential and electric field can be calculated using the Coulomb integral, indicating that the lack of symmetry makes Gauss's Law less useful in this scenario.
  • There is a suggestion that numerical methods may be necessary to solve for the electric field in this case, particularly for finite line charges.

Areas of Agreement / Disagreement

Participants express differing views on the applicability of Gauss's Law to the problem, with some asserting it can be used while others highlight the limitations due to symmetry. The discussion remains unresolved regarding the best approach to calculate the electric field of a charged thread.

Contextual Notes

Participants note the dependence on symmetry for the applicability of Gauss's Law and the potential need for numerical solutions in cases lacking high symmetry.

Guillem_dlc
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Hello,

Can not Gauss's Law be used to calculate the electric field generated by a uniformly charged finite thread?

I suppose it is because I can not consider the electric field constant (always going to the same direction), and for this I would have to do it by parts (the lateral flow, and the flow of the cylinder caps) as if they were two independent geometric objects, which makes it not a closed surface. true?
 
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Guillem_dlc said:
Hello,

Can not Gauss's Law be used to calculate the electric field generated by a uniformly charged finite thread?

I suppose it is because I can not consider the electric field constant (always going to the same direction), and for this I would have to do it by parts (the lateral flow, and the flow of the cylinder caps) as if they were two independent geometric objects, which makes it not a closed surface. true?

I don't quite understand what "... uniformly charged finite thread ... " means. Do you mean a finite line charge?

Note that Gauss's law can be used to calculate ANY type of charge distribution. However, it doesn't mean that it is solvable analytically for those charge distribution. The ones we deal with in intro physics are the ones with high symmetry that allow for the calculation of the electric flux to be simple enough.

So yes, Gauss's law can be used to calculate the electric field (or electric field flux) for a finite line charge. But you will have to solve it numerically, since there isn't a simple analytical solution, except at very far away in the spherical cow regime.

Zz.
 
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ZapperZ said:
I don't quite understand what "... uniformly charged finite thread ... " means. Do you mean a finite line charge?

Note that Gauss's law can be used to calculate ANY type of charge distribution. However, it doesn't mean that it is solvable analytically for those charge distribution. The ones we deal with in intro physics are the ones with high symmetry that allow for the calculation of the electric flux to be simple enough.

So yes, Gauss's law can be used to calculate the electric field (or electric field flux) for a finite line charge. But you will have to solve it numerically, since there isn't a simple analytical solution, except at very far away in the spherical cow regime.

Zz.

Thanks!

Guillem
 
The potential and electric field of a finite uniformly charged thread is readily found from the Coulomb integral.
There is not enough symmetry to make Gauss's law useful.
 

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