Using Isothermally Compressed Air to Cool a Refrigerator

AI Thread Summary
To calculate the amount of isothermally compressed air needed to maintain the temperature of a 14 cf refrigerator at 3 degrees C and an 18 cf freezer at -18 degrees C, one must first determine the final temperature of the air after adiabatic and reversible expansion from 7 psig to 0 psig. This involves applying thermodynamic principles to find the temperature drop during expansion. Once the final temperature is established, the heat transfer required to maintain the desired temperatures in the refrigerator and freezer can be calculated. The volume of air needed per unit time can then be derived from these calculations. Accurate calculations will ensure efficient temperature maintenance in both appliances.
Andy049
Messages
1
Reaction score
0
If I have a steady supply of isothermally compressed air at 7 psi (approximately 148 kPa) at a temperature of 4 degrees C, how would I calculate the amount needed of that air per unit time to maintain the temperature of a 14 cf refrigerator at 3 degrees C? A 18 cf freezer at -18 degrees C?
 
Science news on Phys.org
The first step would be to determine the temperature that the air would attain if it were expanded adiabatically and reversibly from a pressure of 7 psig to a pressure of 0 psig.
 
I need to calculate the amount of water condensed from a DX cooling coil per hour given the size of the expansion coil (the total condensing surface area), the incoming air temperature, the amount of air flow from the fan, the BTU capacity of the compressor and the incoming air humidity. There are lots of condenser calculators around but they all need the air flow and incoming and outgoing humidity and then give a total volume of condensed water but I need more than that. The size of the...
Thread 'Why work is PdV and not (P+dP)dV in an isothermal process?'
Let's say we have a cylinder of volume V1 with a frictionless movable piston and some gas trapped inside with pressure P1 and temperature T1. On top of the piston lay some small pebbles that add weight and essentially create the pressure P1. Also the system is inside a reservoir of water that keeps its temperature constant at T1. The system is in equilibrium at V1, P1, T1. Now let's say i put another very small pebble on top of the piston (0,00001kg) and after some seconds the system...
Back
Top