Using Newton's laws to find an expression for the angle of inclination

AI Thread Summary
The discussion focuses on deriving an expression for the angle of inclination (theta) at which a refrigerator begins to slide, using Newton's laws. Participants emphasize the importance of including the cosine factor to accurately represent the normal force in the friction equation. The correct approach involves setting the net force equal to zero when the refrigerator is on the verge of sliding, leading to the conclusion that acceleration (a) is zero. The final expression discussed is theta = a/g + mu_s*cos(theta), with questions raised about its simplification. The conversation highlights the critical role of understanding forces and angles in solving physics problems related to friction and motion.
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Homework Statement



Use Netwon's laws to find an expression for the angle of incilination theta at which the refrigerator starts to slide. Express your answer in terms of possible g, Us, Uk and m.


Homework Equations



Fnet=ma
Ff=UFn

The Attempt at a Solution



I attached my attempt at the solution, I would like to know if I did it properly or made a mistake somewhere.

Thanks :)
 

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You lost a cosine (or just never included it). See if you can figure out where. That's the only thing I see.
 
taotao said:

Homework Statement



Use Netwon's laws to find an expression for the angle of incilination theta at which the refrigerator starts to slide. Express your answer in terms of possible g, Us, Uk and m.


Homework Equations



Fnet=ma
Ff=UFn

The Attempt at a Solution



I attached my attempt at the solution, I would like to know if I did it properly or made a mistake somewhere.

Thanks :)
The friction force is ## \mu_s N ## where N is the normal force. The normal force here is ## not ## mg. Do you see why?
 
On the third line: Fg x sin theta - Us x mg x cos theta? =ma

The cosine should be there to account for the magnitude of the normal force right?
 
taotao said:
On the third line: Fg x sin theta - Us x mg x cos theta? =ma

The cosine should be there to account for the magnitude of the normal force right?
That's correct!
 
Congrats, good job.
 
For my final answer I get: theta = a/g + mu_s*cos theta
Is there any way to simplify that further?
 
taotao said:
For my final answer I get: theta = a/g + mu_s*cos theta
Is there any way to simplify that further?

I don't see how you get a ## \theta ## alone, outside a trig function.

Also, you are considering the case when it is just about to start sliding. So what is the acceleration then?
 
So a=0 and it would only be mu_S*costheta
 
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