Using the Divergence Theorem to Solve Vector Calculus Problems

SP90
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Homework Statement



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Homework Equations



So I have that v \otimes n = \left( \begin{array}{ccc}<br /> v_{1}n_{1} &amp; v_{1}n_{2} &amp; v_{1}n_{3} \\<br /> v_{2}n_{1} &amp; v_{2}n_{2} &amp; v_{2}n_{3} \\<br /> v_{3}n_{1} &amp; v_{3}n_{2} &amp; v_{3}n_{3} \end{array} \right) <br />

The Attempt at a Solution



I've tried applying the Divergence theorem for Tensors:
<br /> \int_{\partial B} ( v \otimes n )n dA = \int_{B} \nabla \cdot ( v \otimes n ) dV<br />

But that doesn't lead anywhere particularly useful. I thought it might be worth noting that \nabla \cdot ( v \otimes n ) = \frac{dv_{1}}{dx_{1}}n_{1}+\frac{dv_{2}}{dx_{2}}n_{2} + \frac{dv_{3}}{dx_{3}}n_{3} but I can't seem to get anywhere near \nabla v

And this problem isn't homework, it's just an optional exercise, but it's frustrated me for a while and I figured I should get some pointers.
 

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SP90 said:
I thought it might be worth noting that \nabla \cdot ( v \otimes n ) = \frac{dv_{1}}{dx_{1}}n_{1}+\frac{dv_{2}}{dx_{2}}n_{2} + \frac{dv_{3}}{dx_{3}}n_{3} but I can't seem to get anywhere near \nabla v

No it's not! I think you will find (assuming n is constant) that \nabla \cdot ( v \otimes n ) = n \cdot (\nabla v) + n (\nabla \cdot v)

Especially note that it is a vector and not a scalar
 
Isn't \nabla \cdot v \otimes n = (n_{1}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}), n_{2}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}), n_{3}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}))

Which is n \cdot \nabla v?

This would make sense since it gives that

\int_{\partial B} ( v \otimes n )n dA = \int_{B} (\nabla v) ndV

And then since n is just so constant vector, the result follows.

Is that right? Or am I missing something?
 
SP90 said:
Isn't \nabla \cdot v \otimes n = (n_{1}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}), n_{2}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}), n_{3}(\frac{dv_{1}}{dx_{1}}+\frac{dv_{2}}{dx_{2}}+\frac{dv_{3}}{dx_{3}}))

Which is n \cdot \nabla v?

This would make sense since it gives that

\int_{\partial B} ( v \otimes n )n dA = \int_{B} (\nabla v) ndV

And then since n is just so constant vector, the result follows.

Is that right? Or am I missing something?

Of course not; you can't just get rid of the terms that give you trouble... This is what you need to show, but the formula I gave above is still correct.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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