Using the ideal gas law with two unknowns

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SUMMARY

The discussion revolves around solving a problem using the ideal gas law with two unknowns: pressure and temperature after a volume increase. Given an initial volume of V1 = 0.45 x 10-3 m3, pressure p1 = 3.2 MPa, and temperature T1 = 892 K, the volume is increased to V2 = 8 x V1. The ideal gas equation pV = nRT is used, with n = 0.19 moles and R = 8.31 J/moles*K. The correct method to find the new temperature T2 involves using the adiabatic process equation, leading to a temperature of approximately 223 K.

PREREQUISITES
  • Understanding of the ideal gas law (pV = nRT)
  • Knowledge of adiabatic processes in thermodynamics
  • Familiarity with the concept of moles and the ideal gas constant
  • Ability to manipulate algebraic equations for thermodynamic calculations
NEXT STEPS
  • Study the derivation and application of the ideal gas law in various scenarios
  • Learn about adiabatic processes and their equations in thermodynamics
  • Explore the relationship between pressure, volume, and temperature changes in gases
  • Investigate the implications of using different gas constants in calculations
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, particularly those tackling problems involving the ideal gas law and adiabatic processes. It is also useful for educators seeking to clarify concepts related to gas behavior under varying conditions.

kaffekjele
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Homework Statement



You are given a closed container containing a single atom ideal gas.
The volume is V1= 0,45*10^(-3) m^3
Pressure p1 is 3,2 MPa
Temperature, T1, is 892 K

The volume of the gas is increased to V2= 8*V1

Find the pressure and temperature after the increase of volume.


Homework Equations



Ideal gas equation pV=nRT





The Attempt at a Solution



I have n= 0,19 moles from a previous question. R is the ideal gas constant, 8,31 J/moles*K

Manipulating the ideal gas equation for pressure gives me p = (nRT)/V but that leaves T as an unknown so I'm not sure if that's the right way to go...
 
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I would expect that the expansion is adiabatic, this gives another constraint on the gas.
 
I was looking at that and tried to find the new temperature by using T2= T1*(\frac{V1}{V2})\gamma-1 which gave me 221,46K which is not correct according to my lecturer.
 
It would be interesting to see how the lecturer would solve this.
 
kaffekjele said:
I was looking at that and tried to find the new temperature by using T2= T1*(\frac{V1}{V2})\gamma-1 which gave me 221,46K which is not correct according to my lecturer.

I get 223 K. What does your lecturer think about that answer?
 

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