Using volumetric pressure to counter a force

AI Thread Summary
The discussion focuses on a problem involving two opposing cylinders, C1 and C2, with movable pistons and an air pressure change in C1. As the pressure in C1 increases from 150 psi to 157 psi, the shaft connecting the pistons moves 4 inches, which affects the pressure and volume in C2. The application of Boyle's law is debated, with some participants questioning its validity for two separate cylinders and emphasizing the need for constant temperature assumptions. The goal is to determine the dimensions of C2 that allow for the specified shaft movement while minimizing volume. The conversation highlights the importance of understanding the relationship between pressure, volume, and the mechanics of the system.
TaylorTexas
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Homework Statement


There are two opposing cylinders, C1 and C2. Each cylinder is sealed. Each cylinder has a movable piston at one end. The pistons of each cylinder face each other. The pistons are connected to each other by a straight Shaft. C1 is connected to an air supply with an initial air pressure of 150 psi. Over time, the air pressure in the air supply, and thus C1, is increased to 157 psi.

The dimensions of C1 is .5" radius and 5" length. the initial air pressure in C2 is 150 psi. What are the dimensions of C2 (Length and Radius), to allow the Shaft to move 4" in the direction of C2 as the pressure increases 7 psi in C1, with a minimum of volume?

Homework Equations


I have used Boyle's law for two cylinders: P1V1=P2V2

The Attempt at a Solution


As the pressure increases in C1, the shaft begins to move right, decreasing the volume, and increasing the pressure in C2. When the shaft moves 4", the pressure in C1 and C2 are equalized and the shaft movement stops.

P1V1=P2V2
Inserting V=π * r12 * h1, I get
P1(π * r12 * h1)=P2(π * r22 * h2)
Where P1=157, r1=.5", h1=5, P2=150, r2=.4, I solve for h2.
Thus, h2=8.1.
So, I would need C2 to be 8.1" long and .4" radius to allow 4" of shaft movement with a change of 7 psi in C1?
 

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I think you have mistakenly applied Boyle's law to two different gases in two different cylinders?
 
TaylorTexas said:
I have used Boyle's law for two cylinders: P1V1=P2V2

As paisiello2 has pointed out, this does not seem correct. Boyle's law relates the pressure and volume of a fluid in a single cylinder (or other confined fluid) before and after some process takes place, provided that the temperature of the fluid does not change. It does not relate the pressure and volume in two different cylinders (or other separate quantities of fluid).
 
TaylorTexas said:
Over time, the air pressure in the air supply, and thus C1, is increased to 157 psi.

A key assumption has been left out of the problem statement: that the temperature of everything stays the same. I'm assuming that was the intent; otherwise everything gets a lot more complicated.

TaylorTexas said:
What are the dimensions of C2 (Length and Radius), to allow the Shaft to move 4" in the direction of C2 as the pressure increases 7 psi in C1, with a minimum of volume?

That last qualifier, "with a minimum of volume", is important. Is that an exact quote? Is the intent that there should be a minimum change in volume in cylinder C2, or that cylinder C2 should have the minimum possible total volume at the end, consistent with the other quantities in the problem?

TaylorTexas said:
As the pressure increases in C1, the shaft begins to move right, decreasing the volume, and increasing the pressure in C2.

Yes, this looks correct.

TaylorTexas said:
When the shaft moves 4", the pressure in C1 and C2 are equalized and the shaft movement stops.

Yes, this looks ok so far. But the next step is key: if the shaft moved 4 inches, what does that tell you? Specifically, what does it tell you about cylinder C1?
 
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