How to solve cross products in physics problems?

AI Thread Summary
The discussion centers on solving cross products in physics problems using the formula for vector cross products. The user expresses uncertainty about applying the formula to their specific vectors, particularly regarding matrix dimensions. They provide their calculated results for two cross products, which are confirmed as correct by another participant. The conversation clarifies that the formula is indeed applicable to the vectors presented, dispelling confusion about matrix types. Overall, the user successfully computes the cross products and receives validation for their work.
uchicago2012
Messages
74
Reaction score
0

Homework Statement


I'm solving a physics problem using cross products and I think I might be doing the cross products wrong


Homework Equations


I'm using the formula:
a cross b = (a2b3- a3b2)x + (a3b1- a1b3)y + (a1b2- a2b1)z
where a1 = ax, a2 = ay, a3 = az, etc.
I don't know if this formula should be used on matrices like these, esp. the second cross product since its not 3 * 3 or 2 * 2 matrix, which I'm pretty sure is all that the formula is intended for. I had to get off wikipedia because my physics book doesn't go into how to solve cross products and I don't have any algebra books around.

The Attempt at a Solution


The cross products are:
(2.5x - 4.3y + 5.1z) cross (-2.4x + 8.0y - 2.6z)
and
(2.5x - 4.3y + 5.1z) cross (10x + 14y)

I got

(-29.62x - 5.74y + 9.68z) for the first one
and
(-71.4x +51y + 78z) for the second one
 
Physics news on Phys.org
uchicago2012 said:
I don't know if this formula should be used on matrices like these, esp. the second cross product since its not 3 * 3 or 2 * 2 matrix, which I'm pretty sure is all that the formula is intended for.

What matrices? What 3x3 and 2x2? What are you talking about? :confused:
This is the formula for the cross product of two vectors, each of which has 3 components.

uchicago2012 said:

The Attempt at a Solution


The cross products are:
(2.5x - 4.3y + 5.1z) cross (-2.4x + 8.0y - 2.6z)
and
(2.5x - 4.3y + 5.1z) cross (10x + 14y)

I got

(-29.62x - 5.74y + 9.68z) for the first one
and
(-71.4x +51y + 78z) for the second one

The first one that you did checks out fine for me.
 
Last edited:
The second one should be (-71.4x + 51y 78z). So yes, you got them both right.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top