Value of n for the energy level transition that produce lamb

AI Thread Summary
The discussion focuses on determining the initial and final quantum numbers (n) for a hydrogen atom's energy level transition that emits a wavelength of 410.2 nm. The relevant equation used is 1/(lambda) = R * (1/2^2 - 1/n^2), suggesting a connection to the Lyman series. However, confusion arises regarding which series to apply, as the user initially considers Lyman but concludes it is not applicable. The correct values for the quantum numbers are identified as ni = 6 and nf = 2, utilizing the Rydberg equation for hydrogen. This highlights the importance of correctly identifying the series for accurate calculations in quantum transitions.
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Homework Statement



A wavelenght of 410.2*10^-9m is emitted by the hydrogen atom in a high voltage discharge tube. what are the initial and final values of the quantum number n for the energy lvl transition that produces this wavelength?

Homework Equations


1/(lambda) = R * (1/2^2 - 1/n^2): Lyman series?

The Attempt at a Solution


I have used this equation to figure out (lambda) but never the other way around.
I tried to solve for n but it doesn't make sense. How can I know which series to solve n for?
At first I thought that it had to be Lyman as Z=1 for hydrogen and subsequently n=1 but no.
The answer is ni = 6 and nf = 2.
 
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use Rydberg eq.

r.JPG

RH=10973732 m^(-1)
 
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