Variable Homework: Solving for m1 in Gm1m2/r^2

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To solve for m1 in the equation f = Gm1m2 / r^2, one must isolate m1 on one side of the equation. The equation can be rearranged to m1 = fr^2 / (Gm2). Participants emphasize the importance of showing work in algebraic manipulations to receive help. They also discuss the clarity that using TEX or LaTex can provide for subscripts and superscripts in mathematical expressions. Understanding basic algebraic principles is crucial for solving this type of problem effectively.
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Homework Statement



Solve for m1: f= Gm1m2 / r squared

The Attempt at a Solution



How do you solve this?
 
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where is your attempt?

work must be shown b4 we can help, thanks!
 
I have no idea how to solve it.
 
here's a hint: Gm1m2 is simply G times m1 times m2

now what would your steps be?
 
honphysics12 said:

Homework Statement



Solve for m1: f= Gm1m2 / r squared

The Attempt at a Solution



How do you solve this?
Are you kidding? This is very simple algebra. Do you know that for any real numbers a and k, both of them not equal to zero, a*(1/k)*k=a ?

You want m1, but you have it on the right-hand side being multiplied by Gm2/(r^2)

(the digits shown in your equation must be assumed as subscripts; if we use TEX or LaTex, we could show that more clearly)
 
symbolipoint said:
if we use TEX or LaTex, we could show that more clearly

Or by using these tags
- Subscript
- Superscript

The corresponding end tags have a forward slash (/) in front of sub and sup.

Examples: m1 m2
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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