Variable shift positive clamper

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erece
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for the given circuit and waveform , i am not getting how output for ωt < π is Vs + E1 ?
given Vs is input and equal to Vm Sinωt
 
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  • Circuit schematic of a positive clamper with source v_S, capacitor v_C, diode D1, resistor R and battery E1, beside a graph of output v_O against θ = ωt showing a clamped sine waveform labelled v_O = V_m sin θ + V_m + E1.
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When input voltage goes negative, C will charge to a negative voltage. There should be at least a large resistance resistor in series with C to keep it from charging to full voltage.
This is not my speciality, so there is no guarantee that this circuit will work even with a large resistance resistor in series with C.