Variable shift positive clamper

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SUMMARY

The discussion focuses on the output behavior of a variable shift positive clamper circuit, specifically addressing the output for ωt < π, which is determined to be Vs + E1. The input voltage, Vs, is defined as Vm Sinωt. The conversation highlights the necessity of incorporating a large resistance resistor in series with the capacitor (C) to prevent it from charging to full voltage when the input voltage transitions to negative. The circuit's reliability remains uncertain due to the contributor's lack of expertise in this area.

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for the given circuit and waveform , i am not getting how output for ωt < π is Vs + E1 ?
given Vs is input and equal to Vm Sinωt
 

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When input voltage goes negative, C will charge to a negative voltage. There should be at least a large resistance resistor in series with C to keep it from charging to full voltage.
This is not my speciality, so there is no guarantee that this circuit will work even with a large resistance resistor in series with C.
 

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