Varying mass- finding centripetal force

AI Thread Summary
The discussion revolves around calculating the experimental radius in a centripetal force experiment with varying mass while keeping the radius and centripetal force constant. The participant has plotted T^2 against mass and derived a slope of 5.07, which they relate to the equation T^2 = (4π^2rM)/F. They express confusion about how to use the slope to find the radius and whether substituting mg for F is beneficial. Clarification is sought on how to manipulate the equations to derive the radius from the slope, and the importance of knowing either F or r to determine the other is emphasized. The participant is encouraged to ensure proper unit consistency while calculating.
HexRei

Homework Statement


I have another problem with a similar thread title but they are not the same, I'd love help with either or both.

Ran trials with varying mass, but radius and centripetal force as constants. Must find experimental radius from the best fit slope. I have already finished the graph and found the slope. I know the slop is T^2/M, but I don't know how to use that.

Radius = .15
calibration weight 0.050
slope = 5.07

Homework Equations


F=4pi^2rM/T^2

The Attempt at a Solution



T^2=(4pi^2rM)/F I've tried rearranging it many ways but I can't figure out how to use this to determine radius from the slope.

4pi^2*.15M=1/F/T^2
5.92M= 1/F/T^2F*T^2=4pi^2rM
(F*T^2)M=4pi^2r
((F*T^2)M)/4pi^2=r
(.490*T^2)M) /39.47=r

Will subbing in mg for F do anything useful?
 
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HexRei said:
Must find experimental radius from the best fit slope
of which plot ? You vary ##m## and measure ##T## so with the relationship ##T^2 = {4\pi^2mr\over F}## with fixed values for ##r## and ##F## you expect a slope ##T^2\over m## of ##{4\pi^2r\over F}##.

If you know either ##F## or ##r## you can determine the other; you can't determine both from one single slope...
 
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HexRei said:
Ran trials
Please describe the experiment.
HexRei said:
best fit slope
What did you plot against what? If you plotted y against x, rearrange your equation into the form y=cx. Whatever that gives for c is what the slope represents.
 
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Experiment was centripetal apparatus rotating with calibration weight representing Centripetal force (mg) and known mass M (calibration weight removed after calibration). Plot was T^2 vs mass. In this case we weren't looking for F (we know it from mg), just deriving r experimentally and seeing how it compares to our known measured r.
 
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Taking the equation T^2=4π^2rM/F

Can I just calculate 4π2r/F? When I plug in numbers I get 5.92M/F. Can I divide 5.92 by the known F of 4.90? When I do that I get 12.085 but M is still floating up there and the 12.085 isn't very close to my measured slope of 5.07.

And how do I get from here to F?

Thank you so much for the help!
 
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HexRei said:
When I plug in numbers I get 5.92M/F.
Not sure what you mean by M/F there. If you plug in numbers for r and F in 4π2r/F I would expect units s2/kg.
 
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