Vector addition and displacement

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Homework Help Overview

The problem involves calculating the total displacement of a clown during a rodeo, where he runs in multiple directions, including north and at an angle north of east. The context is vector addition in two dimensions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the representation of the clown's path, questioning whether it forms a trapezoid. There are suggestions to use the law of cosines and to resolve vectors into their components for addition. Some participants seek clarification on how to determine the x and y components of the displacements.

Discussion Status

The discussion is active, with participants offering various methods to approach the problem, including vector resolution and the law of sines. There is no explicit consensus on the best method, but multiple strategies are being explored.

Contextual Notes

Participants are working under the constraints of the problem statement and are attempting to clarify their understanding of vector components and the geometric representation of the clown's path.

MIA6
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Homework Statement


During a rodeo, a clown runs 8.0 m north, turns 55 degrees north of east, and runs 3.5 m. Then, after waiting for the bull to come near, the clown turns due east and runs 5.0 m to exit the arena. What is the clown's total displacement?

The Attempt at a Solution


I drew a pic according to the problem, and it looks like a trapezoid, i don't know if it is the right image. How can i find the total displacement's two components? By adding three vectors together? Please explain it to me, thank you.
 
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Try using the law of cosines.
 
but is this a trapezoid?
 
MIA6 said:
but is this a trapezoid?

It might have two sides that are parallel, hard to tell but I don't think that would help you even if it was...
 
Try resolving each vector into its horizontal and vertical components, and then add them.
 
ok, what's 8.0m's x and y component? its y-component is itslef? the same problem with 5m. hope you can give me some details since i really have no clue.
 
MIA6 said:
ok, what's 8.0m's x and y component? its y-component is itslef? the same problem with 5m. hope you can give me some details since i really have no clue.

8.0 meters north means that this displacement has no x component and a y component of + 8.0 meters.

Break into x and y components all three displacement vectors and add all the x and all the y components.
 
Well the 8m is directly north, so expressed in terms of its components, it would be <0,8>, so yes, its y component is itself, and its x component is zero. The 5m vector will be <5,0>, since it has no y component.
 
You could also turn it into a right triangle and solve with the law of sines only. There are quite a few ways to solve for the total displacement.
 
  • #10
MIA6 said:
ok, what's 8.0m's x and y component? its y-component is itslef? the same problem with 5m. hope you can give me some details since i really have no clue.


Assuming that North is the positive y-axis and East is the positive x-axis:
Since 8.0m points due north, its x-component is zero. All it is is a y-component.
 

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