Vector Addition: Calculate Magnitude of Sum

AI Thread Summary
The discussion revolves around calculating the magnitude of the sum of two vectors with magnitudes 20 and 25. The initial attempt used the Pythagorean theorem, resulting in an incorrect value of 32. Further analysis revealed that the maximum magnitude occurs when the vectors are aligned in the same direction, yielding 45, while the minimum occurs when they are aligned in opposite directions, resulting in 5. The correct answer for the magnitude of the sum, based on the possible values provided, is 12. This conclusion highlights the importance of considering vector direction in addition calculations.
joej24
Messages
76
Reaction score
0

Homework Statement


A vector of magnitude 20 is added to a vector of magnitude 25. The magnitude of this sum might be:
a. zero
b. 3
c. 12
d. 47
e. 50


Homework Equations


c ^2 = a^2 + b^2


The Attempt at a Solution



I was not entirely sure on what to do. I tried using the Pythagorean theorem to find the resultant of the 2 vectors and got 32. ( c ^2 = 20^2 + 25^2).
The answer by the way is C.

Thanks!
Joe
 
Physics news on Phys.org
Try do add the vectors in different ways. Then you will get a possible maximal and a minimal value for the magnitude of the resulting vector. All but one possible answers are outside of this region.
 
okay. I got it. The max magnitude of their addition would be when they are parallel in the same direction. mag would = 45. The min would be when they are parallel in the opposite direction. mag would = 5. Therefore the answer is 12. Thanks!
 
Good.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top