Vector components on the tip of hand on a clock

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To solve the physics homework question, the velocity of the clock hand must be calculated at each specified time, considering its circular motion. The components of the velocity will differ based on the position of the hand; for example, at quarter past, the hand is vertical, while at twenty past, it is at an angle. The vertical component will be zero when the hand is horizontal, and the horizontal component will be zero when the hand is vertical. To find the components accurately, use trigonometric functions like cosine and sine based on the angle of the hand. Ultimately, calculating the velocity at each time and breaking it down into components is necessary for the vector diagrams.
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Hiya all, I'm stuck on a physics question set for homework. It asks "draw vector diagrams to scale to show the vertical and horizontal components of the velocity of the tip of the hand at quater-past, twenty past, twenty-five past and half past the hour." The hand is 20cm long so using the circumference formula and dividing it by time, i get 0.00034m/s as the velocity at quater past. I've drawn the hands and the x and y-axis so is the x and y-axis both 0.00034m/s or that x=0.00034m/s and y=om/s? or do i have to work out the velocity of the tip at those points and then work out the components? if so, how do i do that?
thanx.
 
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Yes, you will need to work out the components of motion at each postion. Think about it! How is the motion different at 3 then at 9?
 
so will i have to make the verticle 0?
 
and will the points be 0.2266666m/s at 20 past and 0.0001133333m/s at 25 past and then use FcosA on the points to find the vectors?
 
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