Vector Cross Product: Perpendicular Vectors lV_1 x V_2l

AI Thread Summary
When vectors V_1 and V_2 are perpendicular, their cross product results in a magnitude equal to the product of their magnitudes multiplied by the sine of the angle between them, which is 1 in this case. The cross product yields a vector that is perpendicular to both V_1 and V_2. It is important to note that this discussion is relevant only in three-dimensional space. The initial confusion regarding the formula for the magnitude of the cross product was clarified, confirming it as |V_1| * |V_2| * sin(a). Understanding these properties is crucial for correctly applying vector cross products in physics and mathematics.
horsegirl09
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If vectors V_1 and V_2 are perpendicular, lV_1 x V_2l =? I know that if they are parallel for vector cross product, they equal 0.
 
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horsegirl09 said:
If vectors V_1 and V_2 are perpendicular, lV_1 x V_2l =? I know that if they are parallel for vector cross product, they equal 0.
The cross product is a vector perpendicular to V_1 and V_2. Also V_1 and V_2 don't have to be perpendicular to each other, only not parallel.

Note that this only makes sense in 3 dimensional space.

Further note: the magnitude is |V_1|x|V_2|cos(a), where a is the angle between the vectors. There is a sign ambiguity.
 
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Isn't it |V_1|*|V_2|*sin(a)?
 
ehj said:
Isn't it |V_1|*|V_2|*sin(a)?

You're right - my bad.
 

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