hi, im having a bit of trouble with this problem(adsbygoogle = window.adsbygoogle || []).push({});

Find the parametric equations for the line through the point(0,1,2) that is perpen dicular to the line x=1+t, y=1-t, z=2t and intersects this line.

first i seen that i have a direction vector from the given parametric eqations which is

vector_v= <1,-1,2> and i can get the parallel line to that by taking <1,1,0>,which i will call vector_r, also from the parametric equations.

then to find a line perpendicular to this i take (vector_v) x (vector_r)

(vector_v) x (vector_r) = <-2,2,2>=vector_n

taking point(0,1,2) and vector_n i get

<0,1,2> + t<-2,2,2> = (0-2t)i+(1+2t)j+(2+2t)k =

x=-2t , y=1+2t , z= 2+2t

i was wondering if this is how you would go about solving this problem, if not a push in the right direction would be great.

thanks

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# Vector equations of lines

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