Resolving Vector Forces with Measured Angles | Fz and FH Components"

  • Thread starter Thread starter ur5pointos2sl
  • Start date Start date
  • Tags Tags
    Forces Vector
AI Thread Summary
The discussion focuses on resolving vector forces into z-components (Fz) and horizontal components (FH) using measured angles. The initial confusion arises from the formulas used, with clarification that Fz should be calculated using sine and FH using cosine. The participant correctly applies the formulas for the first angle but mistakenly uses cosine for both components. The conversation then shifts to resolving FH into x- and y-components (Fx and Fy), raising questions about how to determine the angle Phi in a 3-D context. Understanding the distinction between Theta and Phi is crucial for accurately resolving the components.
ur5pointos2sl
Messages
95
Reaction score
0
The question states:
Use the measured angles to resolve each of the forces exerted by the strings into a z-component(Fz) and a horizontal component(FH).

Fz = F cos Theta
FH = F cos Theta

Given angles and forces:

30 deg. 270 N
135 deg. 170 N
240 deg. 260 N

I am a little confused about the problem and what exactly its asking for.

I will just show you my attempt for 30 deg. and see if it is the correct approach.


angle 30 deg
force 270 N
Fz = F cos Theta = 135
FH = F cos Theta = 234

Is this what they mean by a Z component and horizontal?
 
Physics news on Phys.org
Resolving a vector means splitting it up into it's components. What you have is correct except you have cos\Theta in both of them. I assume you meant the two equations to be
F_z = Fsin\theta
F_x = Fcos\theta
You got the right answers so I guess you just meant sin.
 
Jebus_Chris said:
Resolving a vector means splitting it up into it's components. What you have is correct except you have cos\Theta in both of them. I assume you meant the two equations to be
F_z = Fsin\theta
F_x = Fcos\theta
You got the right answers so I guess you just meant sin.

Ok thank you. Now that I have done this there is a second part to the question.

Resolve FH into x- and y- components, Fx and Fy.

Fx=FH cos Phi
Fy=FH sin Phi

How would I use the equations since its Phi instead of Theta. This is a 3-D problem just to make you aware. Therefore, Phi is the angle between FH and the x axis. I am not sure how to get Phi.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top