Vector Manipulation (Orthogonal and Parallel Vectors)

Click For Summary
To determine vectors v and w from a=<2,4,-3> and b=<4,-5,6> such that a=v+w, where v is parallel to b and w is orthogonal to b, v must be expressed as a scalar multiple of b, v=tb. This leads to w=a-v=a-tb, requiring that w.b=0 for orthogonality. By applying the dot product, the equation (a-tb).b=a.b-t(b.b)=0 can be used to solve for the scalar t. The discussion highlights the challenge of finding t and emphasizes the importance of correctly applying vector properties. The participants are working through the mathematical steps to arrive at the solution.
adam199
Messages
17
Reaction score
0
Consider the vectors a=<2,4,-3> and b=<4,-5,6>. Determine vectors v and w such that a=v+w and v is parallel to b while w is orthogonal to b.The dot product of two orthogonal vectors is zero and the cross product of two parallel vectors is zero. A parallel vector is a multiple of the chosen vector.I tried using multiples of b for v and then seeing if random vectors orthogonal to b can be added to v to give a. I'm lost here.
 
Physics news on Phys.org
adam199 said:
Consider the vectors a=<2,4,-3> and b=<4,-5,6>. Determine vectors v and w such that a=v+w and v is parallel to b while w is orthogonal to b.The dot product of two orthogonal vectors is zero and the cross product of two parallel vectors is zero. A parallel vector is a multiple of the chosen vector.I tried using multiples of b for v and then seeing if random vectors orthogonal to b can be added to v to give a. I'm lost here.

Instead of expressing parallel as a cross product, if v is parallel to b then v must be a scalar multiple of b. So v=tb for some t. That means w=a-v=a-tb. Now w.b must be 0. Try to solve for t.
 
Dick said:
Instead of expressing parallel as a cross product, if v is parallel to b then v must be a scalar multiple of b. So v=tb for some t. That means w=a-v=a-tb. Now w.b must be 0. Try to solve for t.

I tried using w=a-tb. I dotted both sides by b, and got 0=(a-tb).b, where t is the only unknown, but I got stuck again. I'm not quite sure how to solve for t at that point.
 
adam199 said:
I tried using w=a-tb. I dotted both sides by b, and got 0=(a-tb).b, where t is the only unknown, but I got stuck again. I'm not quite sure how to solve for t at that point.

Distribute the dot product. (a-tb).b=a.b-t(b.b)=0. Now try it.
 
Dick said:
Distribute the dot product. (a-tb).b=a.b-t(b.b)=0. Now try it.

thanks
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 6 ·
Replies
6
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K