What is the distance and direction between city A and city C?

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To determine the distance and direction from city A to city C, an airplane flies 200 km due west to city B and then 345 km at an angle of 34.5° north of west to city C. The solution involves using the Pythagorean theorem, but since the triangle formed is not right-angled, sine and cosine functions are necessary to find the lengths of the sides. The angle of 34.5° is interpreted as a clockwise rotation from the negative x-axis (west). Ultimately, the calculated straight-line distance from city A to city C is approximately 398.78 km.
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Homework Statement



An airplane flies 200 km due west from city A to city B and then 345 km in the direction of 34.5° north of west from city B to city C. In straight-line distance, how far is city C from city A? Relative to city A, in what direction is city C?


Homework Equations



The Pythagorean theorem


The Attempt at a Solution



398.78 km
 
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The Pythagorean theorem is about right-angled triangles. The triangle ABC in your problem is not right-angled.

The way to solve this would be: draw the situation, then try to make some right-angled triangle, calculate the length of its sides using sine and cosine functions and then use the Pythagorean theorem.
 


I don't know how to draw 34.5 degrees north of west.
 


Yeah I can understand that, I do not find it very clear terminology either, but I am assuming they meant rotating the negative x-axis (i.e. west) 34.5 degrees in clockwise direction (i.e. towards north).
 
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