Velocity and acceleration of an airplane

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Homework Help Overview

The discussion revolves around a physics problem involving the velocity and acceleration of an airplane landing on a carrier deck. The airplane lands at a speed of 150 miles per hour and comes to a stop over a distance of 500 feet. Participants are exploring how to calculate the acceleration and the time required for the airplane to stop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the variables involved, including distance and initial and final velocities. There is an exploration of how to apply kinematic equations to find acceleration and time. Questions arise about the adequacy of the given information and the interpretation of average velocity.

Discussion Status

The discussion is active, with participants attempting to clarify their understanding of the problem and the relevant physics concepts. Some guidance has been offered regarding the use of kinematic equations, and there is a recognition of the need to derive time from average velocity.

Contextual Notes

Participants express uncertainty about the number of variables needed for the calculations and the absence of time in the problem statement. There is a focus on understanding initial and final velocities as well as the implications of average velocity in solving the problem.

aldeemativo
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Homework Statement



VELOCITY AND ACCELERATION:
An airplane lands in a carrier deck at 150 miles per hour and is brought to a stop by an arresting device in 500 feet.

Homework Equations



What is the acceleration?
What is the time required to stop?

The Attempt at a Solution

 
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Welcome to Physics Forums.

You seemed to have missed a section: :wink:
aldeemativo said:

The Attempt at a Solution

 
hootenanny said:
welcome to physics forums.

You seemed to have missed a section: :wink:

what do you mean?
 
aldeemativo said:
what do you mean?
You haven't showed us your attempt at the solution.
 
Hootenanny said:
You haven't showed us your attempt at the solution.

BUT I've got no idea how..., i don't know because the given variables are only two which are: the distance, velocity but in physics formula for the computation of this problem requires three or more than variables given.. could you teach me?
 
aldeemativo said:
BUT I've got no idea how..., i don't know because the given variables are only two which are: the distance, velocity but in physics formula for the computation of this problem requires three or more than variables given.. could you teach me?
You actually know three variables:
  1. Distance
  2. Initial Velocity
  3. Final Velocity
 
Hootenanny said:
You actually know three variables:
  1. Distance
  2. Initial Velocity
  3. Final Velocity

could you tell me what is the initial and final velocity... if i will be able to know that, then i think i could do it... thank you so much...
 
aldeemativo said:
could you tell me what is the initial and final velocity... if i will be able to know that, then i think i could do it... thank you so much...
I'm sure that you could work that out for yourself. You are given the initial speed and you are told that the aircraft comes to rest. What is the aircraft's speed when it isn't moving?
 
Hootenanny said:
I'm sure that you could work that out for yourself. You are given the initial speed and you are told that the aircraft comes to rest. What is the aircraft's speed when it isn't moving?

zero?
 
  • #10
aldeemativo said:
zero?
Exactly :smile:
 
  • #11
Hootenanny said:
Exactly :smile:

oh... so half of 150 gives if velocity = (Final velocity + Initial velocity) / 2, then, it will give me a 75 average velocity right?
 
  • #12
aldeemativo said:
oh... so half of 150 gives if velocity = (Final velocity + Initial velocity) / 2, then, it will give me a 75 average velocity right?
Why are you computing the average velocity?
 
  • #13
aldeemativo said:
oh... so half of 150 gives if velocity = (Final velocity + Initial velocity) / 2, then, it will give me a 75 average velocity right?

THANx Hootenanny... :) i know this is just a simple problem yet i don't know how to solve it... thanks a lot... more powers!
 
  • #14
aldeemativo said:
THANx Hootenanny... :) i know this is just a simple problem yet i don't know how to solve it... thanks a lot... more powers!
You should be able to use kinematic (SUVAT) equations to solve this.
 
  • #15
Hootenanny said:
Why are you computing the average velocity?

To find the time needed to come to a stop with: avg velocity = distance/time
 
  • #16
willem2 said:
To find the time needed to come to a stop with: avg velocity = distance/time

yet there's no time indicated from the given problem making me think about the velocity to get the time... can you help me with this?? thanks a lot...
 
  • #17
v0 = 150 mph = 67.1 m/s
v1 = 0 m/s
\Deltax = 500 ft = 152.4m

use v12 = v02 + 2a\Deltax

I think you can solve it from there?
 
  • #18
aldeemativo said:
yet there's no time indicated from the given problem making me think about the velocity to get the time... can you help me with this?? thanks a lot...

You are on the right track. Use the average velocity to get the time required to stop.

There is also a kinematic formula that can give you the answer directly.
 
  • #19
paisiello said:
You are on the right track. Use the average velocity to get the time required to stop.

There is also a kinematic formula that can give you the answer directly.

i'll try... thank u so much.. :)
 

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