Velocity of 50g Putty+50g Mass After Collision

Thread starter erinbrattin
Start date Aug 28, 2005
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Mass Velocity

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In an inelastic collision involving a 50 g ball of putty moving at 3.0 m/s colliding with a stationary 50 g mass, the principle of conservation of linear momentum applies. The total momentum before the collision equals the total momentum after the collision. The combined mass after the collision is 100 g, and the final velocity can be calculated using the formula: (mass1 * velocity1 + mass2 * velocity2) / (mass1 + mass2). Substituting the values gives a final velocity of 1.5 m/s for the combined mass of putty and the stationary object. This demonstrates how momentum conservation is crucial in solving inelastic collision problems.

Aug 28, 2005

erinbrattin

a 50 g ball of putty moving with a velocity of 3.0 m/s has an inelastic collision head-on with a stationary mass of 50g and sticks to it. find the velocity of the mass and putty after the collision.

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Aug 28, 2005

z-component

Do you remember any equations to use for this type of problem?

Aug 28, 2005

Nenad

just think about that inelastic collision means and use conservation of linear momentum.

Regards,

Nenad

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