Velocity of 50g Putty+50g Mass After Collision

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SUMMARY

The discussion focuses on an inelastic collision involving a 50g ball of putty moving at 3.0 m/s colliding with a stationary 50g mass. The principle of conservation of linear momentum is applied to determine the final velocity of the combined mass after the collision. The formula used is m1v1 + m2v2 = (m1 + m2)v, where m1 and m2 are the masses and v1 and v2 are their respective velocities. The final velocity of the putty and mass after the collision is calculated to be 1.5 m/s.

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  • Understanding of inelastic collisions
  • Knowledge of conservation of linear momentum
  • Familiarity with basic physics equations
  • Ability to perform calculations involving mass and velocity
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erinbrattin
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a 50 g ball of putty moving with a velocity of 3.0 m/s has an inelastic collision head-on with a stationary mass of 50g and sticks to it. find the velocity of the mass and putty after the collision.
 
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Do you remember any equations to use for this type of problem?
 
just think about that inelastic collision means and use conservation of linear momentum.

Regards,

Nenad
 

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