Velocity of Liquid: Pressure & Density Factors

  • Thread starter Thread starter jonnyr
  • Start date Start date
  • Tags Tags
    Liquid Velocity
AI Thread Summary
To determine the velocity of a liquid with a density of 0.885 g/cm³ and a total pressure of 17236.89 kPa, the relevant formula is V² = 2P/D. The area of the nozzle is not required for this calculation, as the focus is on the relationship between pressure, density, and velocity. The nozzle in question has a diameter of 0.16 mm and consists of eight holes. Understanding these parameters allows for accurate calculations of liquid velocity under varying conditions.
jonnyr
Messages
2
Reaction score
0
I am trying to determine the velocity of a liquid. The density of the liquid is .885 g/cm3. The pressure at which it is being forced is 17236.89 kpa. What else do I need to know? I am looking for a formula to help me in other calculations with different pressures and densities. Thanks in advance for any help.
 
Physics news on Phys.org
I assume it is being forced out of a nozzle or hole at that pressure. (Is that the total pressure or pressure above atmospheric?) The main other detail you need is the area of the hole/nozzle, though there is a difference between the measured area and the 'effective' area. That difference can depend on the internal geometry of the container.
 
Yes it is being sprayed from a nozzle in this case which is .16mm per hole and a total of 8 holes. The pressure is total.
 
Correction, you don't need the area - was thinking of a different problem.
Pressure P, velocity V, density D, area A. Power = P.A.V = A.V.D.(V2/2), V2 = 2P/D.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top