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roshan2004
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Can anyone tell me the formula of calculating the velocity of a rolling body down an inclined plane?Please state the quantities as well.
I suspect you mean that there's no energy dissipated due to friction, not that there's no friction. (No slipping.)roshan2004 said:No there is no friction and air resistance.It's chapter is rotational motion.
I'm not quite sure I understand, you want an equation of motion for when the body has left the inclined plane and is now rolling along a horizontal surface?roshan2004 said:I have been given the information about the acceleration of a rolling body down an inclined plane as
a=gsintheta/1+k^2/R^2
But I really want to know the formula of that body when it actually reaches down the inclined plane.
The formula for calculating the velocity of a rolling body down an inclined plane is v = √(2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height of the inclined plane.
The angle of the inclined plane affects the velocity of a rolling body by changing the acceleration due to gravity. The steeper the angle, the faster the body will accelerate and the higher the final velocity will be.
The main difference between the velocity of a rolling body and a sliding body down an inclined plane is that the velocity of a rolling body takes into account the rotational motion of the object, while the velocity of a sliding body only considers its linear motion.
The mass of the rolling body does not affect its velocity down an inclined plane. This is because the formula for calculating velocity (v = √(2gh)) does not include mass as a variable.
No, the velocity of a rolling body can never be greater than the velocity of a free-falling body. This is because the acceleration due to gravity is the same for both objects and the velocity of a free-falling body will always be greater due to the absence of friction on an inclined plane.