Rolling without slipping down an inclined plane

[Ehyeh Asher Ehyeh]

The Nomenclature is not recognized by the disc or the inclined plane. Get it?

 

[Dale]

The Nomenclature is not recognized by the disc or the inclined plane. Get it?

But the formulas are “recognized by the disk” in the sense that one of them correctly describes the behavior of the disk and the other does not. The nomenclature serves to identify which formulas to use.

 

[Ehyeh Asher Ehyeh]

The disc and plane are indifferent to your use of language. The behaviours do not depend on Semantics. That is unless you are talking Voodoo?

 

[Dale]

When a ball/disc slides down an incline plane , the point of contact is moving relative to the surface so the external torque that causes the ball/disc to start rotating is kinetic friction.

IF the ball starts out sliding this is correct. However, note that it is possible (in fact common) for the ball to start rotating in the static friction condition from the beginning. In such cases there would be no “instant the rolling without slipping condition is met” because it would always be met.

An example would be a ball at the top of a rough ramp held in place at the top for a time and then released to roll under gravity. Such a ball would be in the no-slip condition from the beginning.

 

[Dale]

The disc and plane are indifferent to your use of language. The behaviours do not depend on Semantics. That is unless you are talking Voodoo?

I am not talking about semantics at all. Why are you?

 

[dyn]

Physics is great ! You ask a seemingly simple question and it always ends up getting so much more complex. Thanks everyone for replying to this thread

 

[Ehyeh Asher Ehyeh]

The Quantum Froth of physics questions...good one!