Velocity of a wave decreases as the water gets shallow

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The velocity of a wave decreases as water depth decreases, as described by the equations v² = gh and v = fλ. In shallow water, the frequency remains constant while the wavelength decreases, leading to a slower wave velocity at the front compared to the back. This results in the wave's amplitude increasing as it approaches the shore, causing the characteristic breaking of waves. The phenomenon is commonly demonstrated using ripple tanks in educational settings. Understanding this relationship is crucial for studying wave behavior in coastal environments.
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Velocity of a wave decreases as the water gets shallow. As described in-

v*v=gh
(v=velocity
g=gravity
h=depth)

as v=fλ

(λ=wave length
f=frequency)

Either f or λ has to decrease.
But as f is a constant where the same emitter is concerned the wavelength decreases.
Velocity is lower in the front of the wave than the back of it because sea gets shallow near the shore. So the wavelength decreases as it gets to the shore. But the amount of water is the same. So the amplitude has to rise. Water is pushed upwards.

What are yor comments?
 
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There may be some fine points in the equations, but the basic idea is correct. Waves do travel slower in shallow water causing the back end of the wave to squeze toward the front and raise the amplitude. The slowing of the front is what causes the familiar "breaking" of ordinary waves at the shoreline.

The slowing of waves at shallower depth is the basis for "ripple tank" demonstrations of wave phenonomna.
 
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