Velocity of the pressure change

AI Thread Summary
Calculating the pressure rebalancing time in an underwater container involves understanding how pressure changes propagate, typically at the speed of sound in the medium. When a small amount of liquid is removed, only the gravitational pressure of the enclosed liquid remains, while external water pressure is eliminated. Re-pressurizing can be achieved by opening a door, which allows for water displacement and pressure wave propagation. Achieving equilibrium may take longer due to sound waves reflecting within the container. Accurate calculations must consider these dynamics to determine the time required for pressure stabilization.
losbellos
Messages
63
Reaction score
0
Hej guys,

Do you know how to calculate the pressure re balancing time in an underwater container where the liquid were de -pressured by taking very small amount of liquid away (just to have the normal enclosed liquid's gravitational pressure there, without the external water column's pressure). Opening a door would be the method for the re-pressurizing. So calculate instantaneous the water displacement and only the time requires to the pressure wave to balance the pressure needed...

Thank you very much!
 
Physics news on Phys.org
Pressure changes usually propagate with the speed of sound in the medium. Reaching a good equilibrium can need longer in the same way as sound waves can bounce around in a room multiple times.
 
  • Like
Likes losbellos
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top