Velocity Q: 2 Particles Collide in t secs

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Two particles are moving towards each other from a distance of 100 meters, with their velocities defined by the equations v1=3t−5 and v2=−t+30. A participant suggests using integration to find the time of collision by equating the total displacement to 500 meters, which raises confusion since the initial distance is 100 meters. The discussion highlights the need to clarify the distance each particle travels and whether they cover equal distances before colliding. Participants emphasize the importance of correctly interpreting the problem and the equations involved. The conversation ultimately seeks to determine the correct time of collision based on the given velocities and initial distance.
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Homework Statement



Two particles are moving towards each other from 100m apart. The velocity of particle 1 is given by v1=3t−5 and the velocity of the second particle is given by v2=−t+30. At what time (in seconds) do the particles collide?

Homework Equations


D/S=T

The Attempt at a Solution

 
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anyone?
 
Did you make an attempt to solve the problem? Why don't you show it so someone can help guide you to the solution.
 
i generally do understand what to do in this situation.
 
Okay, then post your work. Are you familiar with basic integration techniques?
 
Last edited:
i basically equalled both equations to 500. then i integrated to find when the displacement equals 500. Then i subbed the time back into v equations. After i added the velocity together ,and divided 500/speed.
 
simile said:
equals 500

Why 500? The particles are 100 meters apart, right?
 
simile said:
i basically equalled both equations to 500. then i integrated to find when the displacement equals 500. Then i subbed the time back into v equations. After i added the velocity together ,and divided 500/speed.
Not sure where you are getting 500 from, but my guess is that either it should say 1000m in the OP or in the above you meant 50.
What makes you think that each will cover half the distance?
 

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