Velocity to Keep Object in Orbit Above Moon - Jeffrey

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To determine the velocity needed for an object to maintain orbit just above the moon's surface, one must consider the balance between gravitational force and centripetal force. The gravitational force can be equated to the centripetal force using the formula a (centripetal) = v^2 / r, where r is the moon's mean radius and a (centripetal) is 1.6 m/s². By rearranging this equation, the required orbital velocity can be calculated. The discussion emphasizes the importance of understanding the relationship between these forces in orbital mechanics. This approach provides a straightforward method to solve for the necessary velocity.
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I am trying to find velocity which is needed to keep any object which is in orbit outerspace just above the surface of the moon. Help appriciated...
Jeffrey
 
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Try thinking about this more generally. You have an object moving in a circular path (in this case in orbit around the moon). In order to maintain this path there must be a centripetal force acting, in this case gravity. Write down the gravitational force between the object and the moon and equate it to the centripetal force, the answer should then be just a few lines of algebra away.

Good luck!
 
interesting, a (centripetal) = v^2 over r, where r is mean radius of moon, and a (centripetal) is 1.6 m/s^2, one can solve for v.
I think I got it, thanks buddy.
 
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