Verification of Divergence Theorem

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SUMMARY

The discussion centers on the application of the Divergence Theorem to the vector field F(x,y,z) = (2x-z) i + x²y j + xz² k over the volume defined by the coordinates [0,0,0] and [1,1,1]. The divergence of F was calculated as div F = 2 + x² - 2xz, leading to a volume integral result of 11/12. Participants emphasized the necessity of calculating the flux integral using surface integrals for each face of the cube, employing the identity ∮_S F · d**s**.

PREREQUISITES
  • Understanding of vector calculus, specifically the Divergence Theorem.
  • Familiarity with calculating divergence of vector fields.
  • Experience with triple integrals in three-dimensional space.
  • Knowledge of surface integrals and normal vectors.
NEXT STEPS
  • Study the Divergence Theorem in detail, focusing on its applications in vector fields.
  • Practice calculating divergence for various vector fields, including polynomial functions.
  • Learn how to compute surface integrals over different geometrical shapes.
  • Explore the relationship between flux integrals and surface integrals in vector calculus.
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Students and professionals in mathematics, physics, and engineering who are working with vector fields and need to apply the Divergence Theorem for flux calculations.

sunnyday11
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Homework Statement



F(x,y,z) = (2x-z) i + x2y j + xz2 k and the volume is defined by [0,0,0] and [1,1,1].

Homework Equations



flux integral = \int\int\int div F dV

The Attempt at a Solution



\int\int\int div F dV = \int\int\int (2+x2-2xz)dxdydz

= 2 + 1/3 - 1/2 = 11/12

But I have no idea how to calculate the flux integral because the methods I learned was to use z=f(x,y) with the unit normal vector.

Thank you very much!
 
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But I have no idea how to calculate the flux integral because the methods I learned was to use z=f(x,y) with the unit normal vector.

Thank you very much!

Thats sort of what you have to do, you have to divide your volume into pieces, find a normal for each piece (I assume here that this is a cube with one corner in (0,0,0) and one in (1,1,1)) and do the surface integral for each side (so 6 integrals in the whole).

But use the identity \oint_S = F \bullet d\textbf{s}
 

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