Verification Of Stoke's Theorem

  • Thread starter Thread starter Baumer8993
  • Start date Start date
  • Tags Tags
    Theorem
Baumer8993
Messages
45
Reaction score
0

Homework Statement


Verify Stoke's Theorem by computing both integrals: (stoke's theorem, and the original work integral).
σ is the portion of z = sqrt(4-x2-y2) above the xy-plane and the vector field is F = <2x-y, y*z2, y2z>

Homework Equations


stoke's theorem, and work integral


The Attempt at a Solution


When I do stoke's theorem I get <0,0,1> for my curl F. My normal vector is <2x, 2y, 2z>. After I do the two, and do the integral I get 33.51 for my answer.

My work integral I have <2cos(t), 2sin(t)> for my parametrization path. However, when I do the integral I get 12.5. I am not sure which one is right since I have tried the problem three times, but I always get the same answer, so I do not know what to do.
 
Physics news on Phys.org
Baumer8993 said:

Homework Statement


Verify Stoke's Theorem by computing both integrals: (stoke's theorem, and the original work integral).
σ is the portion of z = sqrt(4-x2-y2) above the xy-plane and the vector field is F = <2x-y, y*z2, y2z>

Homework Equations


stoke's theorem, and work integral


The Attempt at a Solution


When I do stoke's theorem I get <0,0,1> for my curl F. My normal vector is <2x, 2y, 2z>. After I do the two, and do the integral I get 33.51 for my answer.

My work integral I have <2cos(t), 2sin(t)> for my parametrization path. However, when I do the integral I get 12.5. I am not sure which one is right since I have tried the problem three times, but I always get the same answer, so I do not know what to do.

Do you expect us to work both sides out to see what we get? Show us what you did and we can likely quickly find your mistake.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top