Verifying Divergence Theorem on Sphere with F(x,y,z)=zi+yj+xk

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Homework Help Overview

The discussion revolves around verifying the divergence theorem for the vector field F(x,y,z) = zi + yj + xk over the solid sphere defined by x² + y² + z² ≤ 16. Participants are exploring the relationship between the volume integral of the divergence of F and the surface integral of F over the sphere's boundary.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the divergence of F and its implications for the volume integral. Questions arise regarding the integrand used in the volume integral and the necessity of evaluating the integral given that the divergence is constant. There is also a suggestion to independently calculate the total flux using the surface integral to verify the divergence theorem.

Discussion Status

The discussion is active, with participants providing insights and corrections regarding the setup of the integrals. Some guidance has been offered on how to approach the verification of the divergence theorem, including hints on calculating the surface integral. There is no explicit consensus yet on the final approach to take.

Contextual Notes

Participants note the need to verify the divergence theorem and discuss the implications of the divergence being constant. There is an emphasis on using known formulas for the volume of a sphere and the surface integral for flux calculations.

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Homework Statement



Folks,

Verify the divergence theorem for

F(x,y,z)=zi+yj+xk and G the solid sphere x^2+y^2+z^2<=16

Homework Equations



##\int\int\int div(F)dV##

The Attempt at a Solution



My attempt

The radius of the sphere is 4 and div F= 1, therefore the integral becomes

##\int\int\int div(F)dV=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} 1dV=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} 2\rho^2 sin (\phi) d\rho d\phi d \theta##

Is this correct so far?
Thanks
 
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where did the 2 come from in the integrand? Other than that it's right.

EDIT: Also, since divF is a constant and the volume of a sphere can easily be found, you don't actually need to evaluate an integral.
 
cjc0117 said:
where did the 2 come from in the integrand? Other than that it's right.

EDIT: Also, since divF is a constant and the volume of a sphere can easily be found, you don't actually need to evaluate an integral.

Hi, that should be a 1, ie

##...=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} \rho^2 sin (\phi) d\rho d\phi d \theta##
But it says I need to verify the Divergence Theorem...so I guess I can continue and verify?

Thanks
 
\int_0^{2\pi} \int_0^{\pi} \int_0^{4} dV = volume of sphere with radius 4.

Just use the well-known formula for calculating volume of sphere. The answer should obviously be the same as the evaluation of your triple integral expression above.

Now, when you're asked to verify the Gauss Divergence Theorem, you should independently calculate the total flux using the surface integral formula, to confirm your answer.
\iint_S \vec F \hat n \,.d\sigma
Hint: To make it easier, split the sphere exactly in half laterally and evaluate the surface integral for one half. Then multiply by 2 to get the total flux.
 
Last edited:
sharks said:
\int_0^{2\pi} \int_0^{\pi} \int_0^{4} dV = volume of sphere with radius 4.

Just use the well-known formula for calculating volume of sphere. The answer should obviously be the same as the evaluation of your triple integral expression above.

Now, when you're asked to verify the Gauss Divergence Theorem, you should independently calculate the total flux using the surface integral formula, to confirm your answer.
\iint_S \vec F \hat n \,.d\sigma
Hint: To make it easier, split the sphere exactly in half laterally and evaluate the surface integral for one half. Then multiply by 2 to get the total flux.

Ok, thanks guys. Will respond hopefully at some stage.

Cheers
 
Note: d\sigma is the differential area.
 

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