Vertical Motion under Gravity Q)

AI Thread Summary
A stone is thrown vertically upwards at 16 m/s from a height h and hits the ground after 4 seconds. The vertical displacement when the stone hits the ground is equal to -h. Using the kinematic equation, the relationship is established as -h = 16t - 4.9t^2. By substituting t = 4 seconds into the equation, the value of h can be calculated. The discussion focuses on applying kinematic equations to solve for the initial height from which the stone was thrown.
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Homework Statement


Apologies for so many posts, however this is the last question.

A stone his thrown vertically upwards with speed 16m/s from point h meters above the ground. The stone hits the ground 4s later.
Find the value of h.

The Attempt at a Solution


I really haven't a clue on how to start this question, I haven't really encoutered this before, and would end up doing my own sledgehammer way.
But otherwise, can someone people give hints on how to solve this, I know all the kinematic equations, its just this situation confuses me cause of h.

Thanks in advance.
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delta y = (voy)t - 4.9t^2

when the stone hits the ground, its vertical displacement will be the opposite of its initial height ...

delta y = -h

-h = 16t - 4.9t^2

sub in t = 4 ... h = ?
 
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