Very simple inorganic chemical reaction HELP

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The reaction between KBr and NaOH in a boiling solution leads to the formation of KOH and NaBr, which are both soluble in water. The discussion highlights that both reactants and products will dissociate into ions, complicating the observation of any visible reaction. It is suggested that water may act as a reagent due to the NaOH being in solution, potentially resulting in an acidic reaction. However, the solubility of the compounds may mean no noticeable changes occur. Overall, it is characterized as a simple double displacement reaction.
stamba
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Hello.
Can you please help me with this reaction?

* KBr + NaOH --> ?*

Put KBr in boilling solution of NaOH. What are the products?
 
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If I'm not mistaken sorry if I'm wrong on this but I think it should be

KBr + NaOH --> KOH+ NaBr
 
However, all of those will dissociate into ions (on both sides of the equation). Maybe you have to assume that water is a reagant because it is a solution of NaOH, and then it will be an acidic reaction. I may be off though...
 
Maybe you'll observe no visible reaction since both the reactants and products are very soluble. But it should be a simple double displacement reaction I think
 
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