About the stages of a transistor.. Active,Saturation and Cutoff. Active its obviously on and cutoff off. May be a dumb question but is the transistor ON on Saturation mode? Also my textbooks says that when the BE junction is forward bias, Vbe= 0.7V. But at the same time in another problem it says that the cutoff voltage in the BE junction of an NPN transistor is Vbe=0.5V. Which leads to my question, What is the cutoff voltage of the BE junction in an NPN transistor, 0.7V or 0.5V? Is the 0.7 value given as cushion flor the transitor to be fully ON? I'm kind of confused about this whole thing so any help would be appreciated. And lastly, what is the difference of current behavior in Active with Saturation mode? Where is the current the largest?