Very simple spring constant questoin

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Homework Help Overview

The discussion revolves around understanding the spring constant in different orientations of springs, specifically comparing vertical and horizontal setups. Participants are exploring the implications of Newton's laws in these contexts.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions whether the spring constant formula for a vertical spring applies to a horizontal spring on a frictionless surface. Some participants clarify the relationship between force, spring constant, and acceleration in both scenarios, while others raise concerns about the interpretation of forces involved.

Discussion Status

Participants are actively engaging in clarifying concepts related to Newton's second law and the application of spring constants. There is a recognition of the differences between vertical and horizontal cases, and some guidance is offered regarding the interpretation of forces.

Contextual Notes

There is an emphasis on the importance of distinguishing between different forces and their applications in various scenarios, particularly in relation to friction and the specific forces acting on a mass.

The thinker
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Hi,

I've just been thinking about this too much and managed to confuse myself.

Spring constant for a vertical spring: k=mg/[tex]\Delta[/tex]

Is it the same for a horizontal spring on a frictionless surface?

Thanks!
 
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No. Horizontally, it's just F = kx.
 
Limecat said:
No. Horizontally, it's just F = kx.

Thanks

So the "a" in F=ma in the horizontal case is just whatever acceleration the mass is undergoing, rather than g?
 
The thinker said:
Thanks

So the "a" in F=ma in the horizontal case is just whatever acceleration the mass is undergoing, rather than g?

Yes,you are right.
During the horizontal motion

F= ma = kx

And during the vertical motion

F = mg = kx

If friction is taken into count that force also shall be taken into count.
 
Newton's 2nd law says
Sum of Forces = m*a
not just F = m*a

When written as F = ma, this tends to neglect that it is the sum of all forces on the particle (Newton's 2nd law is for a particle).

Writing F = mg is prone to suggest errors. It is safer to write
W = m*g
as a reminder that it is the weight force specifically that is equal to mg.

I am continually amazed at the number of people I see posting here who want to confuse the F's in F = ma and F = mg by setting them equal to each other! There is a dangerous lack of thinking going on.
 

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