Vibrations and Waves: Mass on Incline problem

AI Thread Summary
The discussion revolves around a physics problem involving a mass on an incline supported by a spring that follows Hooke's Law. The mass is 245 g, and the user seeks to calculate the spring constant (k) and the oscillation frequency after a small displacement. The user identifies the need to determine the gravitational force component along the incline and calculates sin(θ) using the triangle formed by the incline. After finding the hypotenuse and calculating sin(θ) as approximately 0.707, the user computes the force exerted on the spring as -1.700 N, indicating progress in solving the problem. The conversation highlights the steps necessary to derive the spring constant and further explore the oscillation frequency.
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Homework Statement


A spring, of negligible mass and which obeys Hooke's Law, supports a mass M on an incline which has negligible friction. The figure below shows the system with mass M in its equilibrium position. The spring is attached to a fixed support at P. The spring in its relaxed state is also illustrated.
Pic link:
http://i995.photobucket.com/albums/af79/huybinhs/plot-2.png

a) Mass M has a value of 245 g. Calculate k, the spring constant.

b) The mass oscillates when given a small displacement from its equilibrium position along the incline. Calculate the oscillation frequency.

2. The attempt at a solution

I know that I need to find the component of the acceleration due to gravity along the inclined plane. From the graph I can find the sinθ. Then find the force which pulls the spring down. Find the extension of the spring and then k.
But I don't know how to get started (no ideas how to get numbers on the graph). Please be a guider! Thanks!
 
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Length of the unstretched spring is 40 cm.
Length of the stretched spring is 50*sqrt(2) cm.
 
rl.bhat said:
Length of the unstretched spring is 40 cm.
Length of the stretched spring is 50*sqrt(2) cm.
Thanks!
So, I got the length of the stretched spring is 70.7 cm.
In order to find k, I need to find F.
F = -mgsin(theta)
then I need to find sin(theta) first.
Could u let me know how to find sin(theta)?
 
sinθ = opposite side/ hypotenuse.
From the graph find these values.
 
Hypotenuse = sqrt[60^2+60^2] = sqrt7200 = 84.85
Sin(theta) = 60/84.85 = 0.707;
F = -1.700 N. Correct?
 
Got it all. Thanks so much rl.bhat ;)
 
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