Viewing Square Wave on Computer Screen: Signal Reduction by 10 dB Explained

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SUMMARY

The discussion focuses on understanding the effect of a 10 dB reduction on a square wave signal generated by a function generator. The original input signal is 1V with an amplitude of 0.5V. The gain in decibels (dB) for voltages is calculated using the formula G(dB) = 20 log(V1/V2). Applying this formula allows users to determine the new voltage level after a 10 dB reduction, which is essential for visualizing the altered waveform on a computer screen.

PREREQUISITES
  • Understanding of square wave signals and their characteristics
  • Familiarity with function generators and their operation
  • Knowledge of decibel calculations for voltage reduction
  • Basic skills in waveform visualization on computer software
NEXT STEPS
  • Learn how to use a function generator to create various waveforms
  • Study the impact of dB changes on different types of waveforms
  • Explore software tools for visualizing waveforms, such as MATLAB or LabVIEW
  • Investigate advanced signal processing techniques for waveform analysis
USEFUL FOR

Electronics students, signal processing engineers, and anyone involved in waveform analysis and visualization will benefit from this discussion.

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Homework Statement


If you had a function generator that generated wave forms so you could veiw them on a computer screen and it was showing a square wave with and input signal of 1V (amplituded 0.5 V) What would it look like if the signal was reduced by 10 dB.


not sure what to do with this can someone help me get started
 
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2slowtogofast said:

Homework Statement


If you had a function generator that generated wave forms so you could veiw them on a computer screen and it was showing a square wave with and input signal of 1V (amplituded 0.5 V) What would it look like if the signal was reduced by 10 dB.


not sure what to do with this can someone help me get started

The gain (or attenuation) in dB for voltages and currents is given by the equation:

G(dB) = 20 log(V1/V2)

(for power gain, it's 10 log(P1/P2)

http://en.wikipedia.org/wiki/Decibel

So put your gain ratio on the LHS of the voltage gain equation, and solve for the ratio of voltages that gives you that gain...
 

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