Violation in superconductivity

In summary, electrons flow forever in a superconducting wire because of zero resistance. The kinetic energy is effectively the potential applied to the superconductor, which allows for no loss in energy. This can be compared to adding water into a circular pipe with no resistance, creating a perpetual flow. However, in a perfect superconductor, there are other losses besides resistance that prevent the current from flowing forever. The current can be maintained for years due to the persistent current in superconducting magnets, which can be measured by the induced magnetic field. The Meissner effect is not applicable in this situation as there is no external magnetic field. Extracting energy from the system will cause the current to dissipate, making it not perpetual motion
  • #36
granpa said:
the magnetic field can be supported without a current by means of the electron spin. what part of that do you not understand.

And you have to show me the origin of the "electron spin" that can produce THAT high of a magnetic field. Calculate the total number of electrons in a supercurrent, and tell me you can get THAT high of a magnetic field produced in those magnets that we use at the LHC or RHIC.

That's absurd!

Not to mention, the Cooper Pairs in most superconductors have ZERO net magnetic moment since they form singlet pairing state!

Zz.
 
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  • #37
Also, you would need to explain why the field generated by these "spins" is proportional the current injected into the solenoid (BEFORE the switch is closed, meaning the solenoid is just an electromagnet with zero dc-resistance, part of a circuit with an external power supply), if these were two different effects (ordinary electromagnet-electron spin) you would expect the field to change when the switch is closed and the solenoid is put into persistent current mode (and it doesn't).

This is incidentally a test first performed by Kammerlingh-Onnes almost 100 years ago.
 
  • #38
ZapperZ said:
And you have to show me the origin of the "electron spin" that can produce THAT high of a magnetic field. Calculate the total number of electrons in a supercurrent, and tell me you can get THAT high of a magnetic field produced in those magnets that we use at the LHC or RHIC.

That's absurd!

Not to mention, the Cooper Pairs in most superconductors have ZERO net magnetic moment since they form singlet pairing state!

Zz.

I am assuming that it isn't the cooper pairs that produce the field. it would be the material itself.
 
  • #39
f95toli said:
Also, you would need to explain why the field generated by these "spins" is proportional the current injected into the solenoid (BEFORE the switch is closed, meaning the solenoid is just an electromagnet with zero dc-resistance, part of a circuit with an external power supply), if these were two different effects (ordinary electromagnet-electron spin) you would expect the field to change when the switch is closed and the solenoid is put into persistent current mode (and it doesn't).

This is incidentally a test first performed by Kammerlingh-Onnes almost 100 years ago.

the spin is proportional to the field that tries to collapse.
 
  • #40
granpa said:
I am assuming that it isn't the cooper pairs that produce the field. it would be the material itself.

Then tell me why this occurs ONLY IN THE SUPERCONDUCTING STATE, and not in the normal state, i.e. you can't get any persistent current (and the resulting induced magnetic field) in the normal state!

I still want you to calculate the total magnetic moment of ALL the electrons in the material and tell me you can get anything above 1 Tesla.

Zz.
 
  • #41
ZapperZ said:
Then tell me why this occurs ONLY IN THE SUPERCONDUCTING STATE, and not in the normal state, i.e. you can't get any persistent current (and the resulting induced magnetic field) in the normal state!
.

because superconductivity=superdiamagnetism. its the diamagnetism that drives the electrons to form cooper pairs.
 
  • #42
f95toli said:
As I wrote above: Hook up a multimeter in parallel to the switch, open switch, observe current decay.

I do this on a pretty regular basis since I work with superconducting magnets and have built a few of the myself (low field ones, with a simple heat switch). The test above is what I use to test the quality of the joint where I crimp the two ends of the wire that makes up the coil together. My joints are pretty bad compared to what you find in commercial magnets (they are welded) but even in my coils the current does not change much (a few percent) over a period of a few hours, the only reason why it drops at all is because of the joint (which is a "weak" superconductor, some of the supercurrent is probably carried by Josepshon current and is not completely dissipationless)

I think I misunderstood what you were saying. yes you will observe a voltage when you open the switch but that's because the magnetic field is collapsing through the opening.
 
  • #43
granpa said:
because superconductivity=superdiamagnetism. its the diamagnetism that drives the electrons to form cooper pairs.

Whaaat?!

You just told me that this has nothing to do with the Cooper pairs. Now you are using THEM to justify the presence of the magnetic field!

Please make valid citations to back up ALL of your claims here, because I think you know what's coming next.

Zz.
 
  • #44
granpa said:
I think I misunderstood what you were saying. yes you will observe a voltage when you open the switch but that's because the magnetic field is collapsing through the opening.

Why would I measure the voltage? It is much better to use the multimeter as an ammeter and measure the current directly instead.
And, as I wrote above, what I (and everyone else) observe is that the current coming out from the solenoid is initially (it obviously decays, but pretty slowly if the initial current is a couple of amps and a good multimeter is used) just a few percent lower than the current I injected into the solenoid a few hours earlier.

Also, you DO realize that you are essentially proposing a new theory for conventional superconductivity? The BCS theory is perhaps the best verified theory there is in condensed matter physics, so you will find it very difficult to persuade people that it is wrong.
Both me and ZapperZ and have spent many years working with superconductors so it is not like we don't know anything anything about the topic.
 
  • #45
ZapperZ said:
Whaaat?!

You just told me that this has nothing to do with the Cooper pairs. Now you are using THEM to justify the presence of the magnetic field!

Please make valid citations to back up ALL of your claims here, because I think you know what's coming next.

Zz.

you're playing it a little fast arent you? I said just the opposite.
 
  • #46
f95toli said:
Why would I measure the voltage? It is much better to use the multimeter as an ammeter and measure the current directly instead.
And, as I wrote above, what I (and everyone else) observe is that the current coming out from the solenoid is initially (it obviously decays, but pretty slowly if the initial current is a couple of amps and a good multimeter is used) just a few percent lower than the current I injected into the solenoid a few hours earlier.

Also, you DO realize that you are essentially proposing a new theory for conventional superconductivity? The BCS theory is perhaps the best verified theory there is in condensed matter physics, so you will find it very difficult to persuade people that it is wrong.
Both me and ZapperZ and have spent many years working with superconductors so it is not like we don't know anything anything about the topic.

you can't put an ammeter is parrallel with a closed superconducting ring and measure anything. ammeters have internal resistance. no current would flow through it.I very much doubt that there is any conflict with BCS theory.
 
  • #47
granpa said:
you're playing it a little fast arent you? I said just the opposite.

Who can tell anymore since none of what you said made any sense, nor backed by any physics that we know. For instance, do you also deny you said this:

its the diamagnetism that drives the electrons to form cooper pairs.

I would like you, before you do anything else, show me valid citation to back this claim. This will be the last request I will ask. Show me how this doesn't conflict with BCS theory.

Zz.
 
  • #48
ZapperZ said:
Who can tell anymore since none of what you said made any sense, nor backed by any physics that we know. For instance, do you also deny you said this:
I would like you, before you do anything else, show me valid citation to back this claim. This will be the last request I will ask. Show me how this doesn't conflict with BCS theory.

Zz.

what is diamagnetism? its the tendency for the electrons in the material to orient themselves in such a way that they cancel out any field present at that point. its exactly what you would expect 2 electrons to do. they orient themselves so that they cancel out each others field.

it is upon you to show that there is any conflict.

finally: I am not trying to prove anything to anybody. you can believe anything you want. I really don't care.
 
  • #49
granpa said:
what is diamagnetism? its the tendency for the electrons in the material to orient themselves in such a way that they cancel out any field present at that point. its exactly what you would expect 2 electrons to do. they orient themselves so that they cancel out each others field.

This is nonsense. If that is true, then ALL metal can become superconductors. Yet, this is false and that only certain metals (and ceramics) can become superconductors. This clearly implies that the drive into superconductivity is governed by something BEYOND just the electron spin. You are also ignorant of the fact that the Ruthenates have spin TRIPLET state where the electrons have spin alligned PARALLEL to each other. This has falsified your faulty understanding of superconductivity.

I think I've read enough nonsense here. If the OP still has a question, he/she can PM me and we'll reopen this thread. Till then, this is done.

Zz.
 

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