Viscous drag parallel to the axis of rotation: Control Systems

[kostoglotov]

Homework Statement

https://i.imgur.com/WPAKuf4.png

seeking G(s) = \frac{\theta_2(s)}{\tau(s)}

Homework Equations

The Attempt at a Solution

What does it mean when the viscous drag is parallel to the axis of rotation?[/B]

It also turns out that this system needs two equations. I can sort of see why, even though it doesn't have two masses, I'm not 100% sure though, how to break this system up into two equations, where and how to make the break.

Any help at all would be very appreciated, thank you :)

 

[Nidum]

That is a truly awful diagram .

Nevertheless it is possible to work out what the various bits do if we assume that this is a purely rotary system .

Those damper terms and the energy accumulator term all act in a rotary sense and not in the linear sense depicted . You can infer this anyway from their dimensions - they are all quoted as being per radian .

 

[rude man]

Homework Statement

View attachment 210469

https://i.imgur.com/WPAKuf4.png

seeking G(s) = \frac{\theta_2(s)}{\tau(s)}

Homework Equations

The Attempt at a Solution

What does it mean when the viscous drag is parallel to the axis of rotation?[/B]

poor statement but just assume there is rotational drag torque in those three places.

It also turns out that this system needs two equations. I can sort of see why, even though it doesn't have two masses, I'm not 100% sure though, how to break this system up into two equations, where and how to make the break.

I would label the right-hand side of the rotor θ₁, then you can have θ₁/τ as the 1st equation and θ₂/θ₁ as the 2nd equation, then multiply the two transfer functions to get θ₂/τ.