Visualizing the Dot Product Inequality of a, b & c in R^d

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The discussion focuses on visualizing the dot product inequality a·b < c·b for vectors a, b, and c in R^d. It suggests that this inequality can be interpreted geometrically, indicating that vector a has a smaller component in the direction of vector b compared to vector c. The dot product can be represented as a rectangle, where the area corresponds to the product of the magnitudes of the vectors and the cosine of the angle between them. This geometric interpretation helps clarify the relationship between the vectors involved. Overall, the exploration seeks deeper insights into the geometric implications of the dot product inequality.
shybishie
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Suppose I have three vectors a,b and c in R^d, And, I have that a.b < c.b(assume Euclidean inner product). What are the ways to visualize relation between a,b and c geometrically? I realize this is slightly open-ended, but am looking for insight here. Thanks in advance.

PS: I have a thought or two, but I'd like to hear feedback before I give my view of the situation.
 
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\vec{a} \cdot \vec{b} &lt; \vec{c} \cdot \vec{b} can be interpreted geometrically as \vec{a} having less of a component in the direction of \vec{b} than does \vec{c}. Or \vec{a} has a more negative component than \vec{c}.
 
Thank you, markly. In retrospect, I should have framed this question to be less trivial sounding than it came out.
 
The dot product \vec{a} \cdot \vec{b} can be visualized as a rectangle (see orange rectangle http://www.ies.co.jp/math/java/vector/naiseki_e/naiseki_e.html" ) having sides of length |\vec{a}| and |\vec{b}| \mathrm{cos(\alpha)}.

This is because \vec{a} \cdot \vec{b} = |\vec{a}| \cdot |\vec{b}| \mathrm{cos(\alpha)}
 
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